BD 我下周考 D是对的
{:6_299:} 本帖最后由 一道爱人试题 于 2013-3-13 10:51 编辑
6楼正解。
本帖最后由 一道爱人试题 于 2013-3-13 10:55 编辑
只能说route-map理解的不够深入，结合五道实验题之一的那个基于策略的路由那道，就理解了。
2.20的题库基本是没有错误的答案的该纠正的都纠正了 TOBEACCIE 发表于 2013-3-12 12:35 static/image/common/back.gif
d选项的结果是：上面原来45不会变，而受影响的是中间的百分之20， 因为MED大，所以不被优先考虑，从而改走 ...
怎么可能不影响原来的45%,注意我说的默认ACL的最后一句Deny Any Any <--------它这句是干嘛的?就是干掉了原来的45%. 如果E因为Deny Any Any的影响只学到45%流量的路由，那E其他流量的路由怎么学习？不能断了吧 这个解答是选的B D
http://www.digitaltut.com/bgp-questions-5 In answer C & B (combined), the MED for prefix 10.10.1.16/28 through router A is set to 150. This would make traffic for this route (45%) go through router B (because the MED default value is 0, which is lower than 150). Since the access-list will also NOT match prefixes: 10.10.1.32/28 & 10.10.1.48/28 – traffic for these two prefixes will be forwarded just normally (via the routing table) ->
Traffic for prefix: 10.10.1.32/28 will continue to go via the upper E-A link (now just 20% total load), while traffic for prefixes 10.10.1.16/28 and 10.10.1.48/28 will be going through the lower F-B link (now 65% total load) -> Original unbalanced (65/20) load is maintained, although it has been reversed between the upper (A-E) and lower (B-F) link -> C is not correct.
For more information about Policy-based routing matches you can read this article: http://www.ciscopress.com/articles/article.asp?p=426637&seqNum=2
If answer D is applied for router A, the MED for 10.10.1.32 set to 150 would make traffic for this route go through router B (because the MED default value is 0, which is lower than 150). So router A will be responsible for 45% traffic and router B will receive 40% traffic -> D is correct. 看来这个题目还是没有最终的结果啊，亏了这么多过NP的 闫辉CCNP 642-902 V200题库视频讲解 里很清晰说明了正确答案是 BD 应该是BD，我今天选BC错啦，总共就错这道，
只要影响一个20%的流量，其它不变，就负载成了45%和40%，D才是最好的选择！！！！害我没千分
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